7n^2-61n+40=0

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Solution for 7n^2-61n+40=0 equation: 



7n^2-61n+40=0

a = 7; b = -61; c = +40;
Δ = b2-4ac
Δ = -612-4·7·40
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-51}{2*7}=\frac{10}{14}
=5/7
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+51}{2*7}=\frac{112}{14}
=8
$

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